(1/(x-4))-(25/(x^2))

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Solution for (1/(x-4))-(25/(x^2)) equation:


D( x )

x-4 = 0

x^2 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:4) U (4:+oo)

1/(x-4)-(25/(x^2)) = 0

1/(x-4)-25*x^-2 = 0

1/(x-4)-25/(x^2) = 0

(1*x^2)/(x^2*(x-4))+(-25*(x-4))/(x^2*(x-4)) = 0

1*x^2-25*(x-4) = 0

x^2-25*x+100 = 0

x^2-25*x+100 = 0

x^2-25*x+100 = 0

DELTA = (-25)^2-(1*4*100)

DELTA = 225

DELTA > 0

x = (225^(1/2)+25)/(1*2) or x = (25-225^(1/2))/(1*2)

x = 20 or x = 5

(x-5)*(x-20) = 0

((x-5)*(x-20))/(x^2*(x-4)) = 0

((x-5)*(x-20))/(x^2*(x-4)) = 0 // * x^2*(x-4)

(x-5)*(x-20) = 0

( x-20 )

x-20 = 0 // + 20

x = 20

( x-5 )

x-5 = 0 // + 5

x = 5

x in { 20, 5 }

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